Grade 9 Mathematics New Book 2026-2027 Session textbook cover featuring geometric shapes, a house, angle of elevation and depression diagrams, with a blue, green, and white design.

Unit 2: Class 9 Math PECTAA Notes New Book

Introduction

HSA Notes brings short, clear, exam focused notes designed to help Class 9 SSC Part One students score 90 plus marks in Punjab Board exams. This page covers Unit 2, Logarithms, spanning Exercise 2.1 through Exercise 2.4, along with the Review Exercise, giving a complete, fast revision resource for the entire unit.

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HSA Notes Features

  • Very short, easy to remember definitions.
  • Step by step solved answers for every question.
  • Quick tricks and memory aids for faster revision.
  • Exact alignment with the PCTB and PECTAA textbook.
  • Scientific notation and log conversions simplified into clear methods.
  • Past paper pattern questions included throughout.
  • A fast revision format built for last minute review.
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Available Across All Punjab Boards and Top Schools

These notes are built for students across all Punjab Boards, including Lahore, Gujranwala, Rawalpindi, Faisalabad, Bahawalpur, Multan, Sargodha, Sahiwal, and DG Khan, and are used at top schools including The City School, Beaconhouse School System, Roots International Schools, Lahore Grammar School, Karachi Grammar School, Froebel’s International School, The Educators, Army Public School, Divisional Public School, and Government Model School.

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Exercise 2.1, Scientific Notation

Express in scientific notation

No.NumberScientific Notation
i2,000,0002.0 times 10 to the power 6
ii48,9004.89 times 10 to the power 4
iii0.00424.2 times 10 to the power negative 3
iv0.00000099.0 times 10 to the power negative 7
v73 times 10 cubed7.3 times 10 to the power 4
vi0.65 times 10 squared6.5 times 10 to the power 1

Express in ordinary notation

No.Scientific NotationOrdinary Notation
i8.04 times 10 squared804
ii3 times 10 to the power 5300,000
iii1.5 times 10 to the power negative 20.015
iv1.77 times 10 to the power 717,700,000
v5.5 times 10 to the power negative 60.0000055
vi4 times 10 to the power negative 50.00004

Applied examples

  • Speed of light, 3 times 10 to the power 8 meters per second, equals 300,000,000 meters per second.
  • Earth’s circumference, 40,075,000 meters, equals 4.0075 times 10 to the power 7 meters.
  • Mars diameter, 6.779 times 10 cubed kilometers, equals 6,779 kilometers.
  • Earth diameter, 1.2756 times 10 to the power 4 kilometers, equals 12,756 kilometers.

Exercise 2.2, Logarithmic and Exponential Form

Express in logarithmic form

No.Exponential StatementLogarithmic Form
i10 cubed equals 1000log base 10 of 1000 equals 3
ii2 to the 8th equals 256log base 2 of 256 equals 8
iii3 to the negative 3 equals 1 over 27log base 3 of 1 over 27 equals negative 3
iv20 squared equals 400log base 20 of 400 equals 2
v16 to the negative one quarter equals one halflog base 16 of one half equals negative one quarter
vi11 squared equals 121log base 11 of 121 equals 2
viip equals q to the power rlog base q of p equals r
viii32 to the negative one fifth equals one halflog base 32 of one half equals negative one fifth

Express in exponential form

No.Logarithmic StatementExponential Form
ilog base 5 of 125 equals 35 cubed equals 125
iilog base 2 of 16 equals 42 to the 4th equals 16
iiilog base 23 of 1 equals 023 to the 0 equals 1
ivlog base 5 of 5 equals 15 to the 1st equals 5
vlog base 2 of one eighth equals negative 32 to the negative 3 equals one eighth
vilog base 9 of 3 equals one half9 to the one half equals 3
viilog of 100,000 equals 510 to the 5th equals 100,000
viiilog base 4 of one sixteenth equals negative 24 to the negative 2 equals one sixteenth

Exercise 2.3, Characteristics, Mantissa, and Antilogs

Find the characteristic

No.NumberCharacteristic
i5,2873
ii59.281
iii0.0567negative 2
iv234.72
v0.000049negative 5
vi145,0005

Find the logarithm

No.ValueApproximate Log
i431.6335
ii5792.7627
iii1.9820.2971
iv0.0876negative 1.0575
v0.047negative 1.3279
vi0.000354negative 3.4510

From a given logarithm

No.Statement
ilog 3177 equals 3.5019
iilog 31.77 equals 1.5019
iiilog 0.03177 equals negative 1.4981

Find x, antilog

No.Givenx
ilog x equals 0.0065approximately 1.015
iilog x equals 1.192approximately 15.55
iiilog x equals negative 3.434approximately 0.000368
ivlog x equals negative 1.5726approximately 0.02676
vlog x equals 4.3561approximately 22,700
vilog x equals negative 2.0184approximately 0.00959

Exercise 2.4, Laws of Logarithms

Evaluate

No.ExpressionResult
ilog base 2 of 18 minus log base 2 of 91
iilog base 2 of 64 plus log base 2 of 27
iiione third log base 3 of 8 minus log base 3 of 18negative 2
iv2 log 2 plus log 252
vone third log base 4 of 64 plus 2 log base 5 of 255
vilog base 3 of 12 plus log base 3 of 0.251

Write as a single logarithm

No.ExpressionSingle Log Form
ione half log 25 plus 2 log 3log 45
iilog 9 minus log one thirdlog 27
iiilog base 5 of b squared, times log base a of 5 cubed6 log base a of b
iv2 log base 3 of x plus log base 3 of ylog base 3 of x squared y
v4 log base 5 of x minus log base 5 of y plus log base 5 of zlog base 5 of x to the 4th, z, over y
vi2 ln a plus 3 ln b minus 4 ln cln of a squared b cubed over c to the 4th

Expand

No.ExpressionExpanded Form
ilog of 11 over 5log 11 minus log 5
iilog base 5 of the quantity 8a to the 6th, all to the one halfthree halves log base 5 of 2, plus 3 log base 5 of a
iiiln of a squared b over c2 ln a plus ln b minus ln c
ivlog of xy over z, all to the one ninthone ninth times the quantity log x plus log y minus log z
vln of 16x cubed, all to the one thirdfour thirds ln 2, plus ln x
vilog base 2 of the quantity 1 minus a over b, all to the 5th5 times the quantity log base 2 of 1 minus a, minus log base 2 of b

Find x

No.Equationx
ilog 2 plus log x equals 15
iilog base 2 of x plus log base 2 of 8 equals 54
iii81 to the x equals 243 to the x plus 2negative 10
ivone twenty seventh to the x minus 6, equals 275
vlog of 5x minus 10 equals 222
vilog base 2 of x plus 1, minus log base 2 of x minus 4, equals 217 over 3

Values using a log table

No.ExpressionApproximate Value
i3.68 times 4.21, over 5.234approximately 2.954
ii4.67 times 2.11 times 2.397approximately 23.458
iii20.46 squared, times 2.4122, over 754.3approximately 1.327
ivthe cube root of 9.364 times 21.64 over 3.21given as approximately 14.138

A note on the last entry above: solving this expression directly gives 9.364 times 21.64, divided by 3.21, which comes to approximately 63.1, and the cube root of 63.1 is approximately 3.98, not 14.138. This looks like a possible transcription issue in the original source rather than an error in the underlying method, so it is worth checking this specific value against your textbook or the original PDF before relying on it.

Applied word problems

  • Earthquake magnitude works out to 3.
  • An investment doubles in approximately 14.2 years.
  • Temperature at 500 meters works out to approximately 17.18 degrees Celsius.

Review Exercise 2

Multiple Choice Questions

No.Answer
ic, 5,200,000
iib, 3.4 times 10 to the power negative 4
iiib, 10
ivd, 3
va, 2
vic, 2.3010
viid, undefined
viiic, 4
ixd, log 15
xc, log base 3 of 81 equals 4

Additional Review Answers

  • Scientific notation: (i) 5.67 times 10 to the power negative 4, (ii) 7.34 times 10 squared.
  • Ordinary notation: (i) 2,600, (ii) 0.0008794, (iii) 0.000006.
  • Logarithmic form: (i) log base 3 of 2187 equals 7, (ii) log base a of c equals b, (iii) log base 12 of 144 equals 2.
  • Exponential form: (i) 4 to the x equals 8, (ii) 9 cubed equals 729, (iii) 4 to the 5th equals 1024.
  • Find x: (i) x equals 3, (ii) x equals negative one half, (iii) x equals negative 0.6.
  • Single logarithm: (i) log of x to the 7th over y to the 6th, (ii) log 2, (iii) log base 5 of 2.
  • Expand: (i) log x plus log y plus 6 log z, (ii) five sixths log base 3 of m, plus one half log base 3 of n, (iii) three halves log 2, plus three halves log x.
  • Values: (i) approximately 4.085, (ii) approximately 1,133, (iii) approximately 24.02.
  • Population works out to approximately 2,035.

View the full PDF for diagrams and constructions supporting every answer above.

Why This Unit Matters for Your Overall Score

Logarithms is a unit that rewards careful, methodical work far more than memorization, since almost every question relies on a small set of core rules, the product rule, the quotient rule, and the power rule, applied correctly and in the right order.

Getting comfortable converting between logarithmic and exponential form early in Exercise 2.2 makes every later exercise easier, since solving for x in Exercise 2.4 almost always comes back to that same conversion. Since this unit also connects directly to scientific notation, a skill used throughout science subjects as well, time spent mastering Unit 2 pays off well beyond the Mathematics paper alone.

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Frequently Asked Questions

Which exercises are covered in these Unit 2 notes? Exercise 2.1, Exercise 2.2, Exercise 2.3, Exercise 2.4, and the Review Exercise are all covered in full.

Does this unit cover both logarithms and scientific notation? Yes, Exercise 2.1 covers scientific notation, while Exercise 2.2 through 2.4 and the Review Exercise cover logarithmic form, characteristics and mantissa, antilogs, and the laws of logarithms.

Are log table based calculations included? Yes, characteristic and mantissa calculations, along with antilog and log table based value problems, are covered in Exercise 2.3 and 2.4.

Are these notes aligned with the PCTB and PECTAA textbook? Yes, these notes are built to exactly match the PCTB and PECTAA New Book for Class 9 Mathematics.

Conclusion

With Exercise 2.1 through 2.4 and the Review Exercise fully solved, from scientific notation through the laws of logarithms, Class 9 students have a complete, exam ready resource for Unit 2. Use these notes alongside regular practice with past papers to build the confidence needed for 90 plus marks in your Punjab Board exam.

Best of luck for your Class 9 Mathematics exam!