Solved Notes Chapter 2 Force and Motion All Punjab Boards Class 11 Physics New Course PCTBB PECTAA Cantab

Comprehensive solved notes on Chapter 2 Force and Motion for Class 11 Physics students under all Punjab Boards including PCTBB, PECTAA, Lahore Board, Faisalabad Board, Multan Board, etc. Similar to high-quality notes in institutions like Punjab College, Superior College. Prepared by Hamdard Science Academy for the new course (Cantab publisher). Covers scalars, vectors, addition/subtraction, resolution, motion types, displacement, velocity, acceleration, equations of motion, projectile motion, Newton’s laws, friction, centripetal force. Includes solved examples, derivations, MCQs, short questions, long questions, numericals, assignments. For complete guide, solutions, easy notes, help, download full PDF at http://hsanotes.com.

1. Basic Concepts of Scalars and Vectors in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

Scalars: Magnitude only, no direction. Examples: mass 5 kg, temperature 30°C, time 10 s, speed 50 m/s, distance 100 m, energy 500 J.

Vectors: Magnitude and direction. Examples: displacement 10 m North, velocity 20 m/s East.

Explanation: Scalars use arithmetic; vectors use rules like head-to-tail.

For more on scalars and vectors in chapter 2 force and motion all Punjab boards class 11 physics, read PDF.

2. Representation of Vectors in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

Graphical: Arrow length magnitude, head direction.

Rectangular components: Vx = V cosθ, Vy = V sinθ.

For detailed explanations and short questions on vector representation in chapter 2 force and motion, check PDF solutions.

3. Addition and Subtraction of Vectors in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

Head-to-tail method, parallelogram law.

Resultant R = √(A² + B² + 2AB cosθ).

Subtraction: A – B = A + (-B).

Solved Example: Vectors 3 m East, 4 m North; resultant 5 m Northeast.

Assignments and numericals solved in PDF for chapter 2 force and motion all Punjab boards class 11 physics.

4. Resolution of Vectors in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

Into components: Fx = F cosθ, Fy = F sinθ.

Applications in equilibrium.

Use PDF for more solved MCQs and long responses on vector resolution in chapter 2 force and motion.

5. Displacement, Velocity, Acceleration in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

Displacement: Vector change in position.

Velocity: Displacement/time, average/instantaneous.

Acceleration: Velocity change/time.

Equations: v = u + at, s = ut + ½at², v² = u² + 2as.

For applications and short questions, read PDF guide.

6. Motion in Two Dimensions – Projectile Motion in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

Horizontal vx = v cosθ, vertical vy = v sinθ – gt.

Range R = (v² sin2θ)/g, max height h = (v² sin²θ)/2g.

Solved Example: Angle 45° max range.

Solved problems in PDF.

7. Newton’s Laws of Motion in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

1st: Inertia.

2nd: F = ma.

3rd: Action-reaction.

Applications: Atwood machine.

Derivations in PDF.

8. Friction and Centripetal Force in Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

Friction: Kinetic μk N, static μs N.

Centripetal F = mv²/r.

Banking θ = tan⁻¹(v²/rg).

More in PDF.

Solved MCQs Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

  1. Vector quantity: (c) Velocity
  2. Resultant of perpendicular vectors: (a) √(A² + B²)

More solved MCQs in PDF.

Short Questions and Responses Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

2.1 Difference scalar/vector: Scalar magnitude only; vector magnitude + direction.

Full solved short questions in PDF.

Long Questions and Responses Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

2.1 Explain vector addition methods: Head-to-tail, parallelogram, with examples.

Full solved long questions in PDF.

Solved Numericals and Assignments Chapter 2 Force and Motion All Punjab Boards Class 11 Physics

2.1 Vectors A=3i+4j, B=5i-2j; A+B=8i+2j, magnitude √68.

Assignment: Projectile v=20 m/s, θ=30°; range ≈ 35.3 m.

Full solved numericals and assignments in PDF for easy notes and solutions.

For complete help, guide, solutions on chapter 2 force and motion all Punjab boards class 11 physics new course PCTBB PECTAA Cantab, visit http://hsanotes.com to read or download PDF.

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