Class 11 Physics Chapter 3 Circular and Rotational Motion Notes PDF – Punjab Board New Course 2025-2026

Ace Chapter 3 Circular and Rotational Motion (New Course 2025-2026) with hsanotes.com notes – guaranteed 90+ marks in Punjab Board exams!

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For students of: All Punjab Boards (BISE Lahore, Gujranwala, Multan, Faisalabad, Sargodha, Rawalpindi, DG Khan, Bahawalpur, Sahiwal) and top schools: Aitchison College, Lahore Grammar School, Beaconhouse, The City School, LACAS, Convent of Jesus & Mary, DPS Lahore, Garrison Academy, Bloomfield Hall, Sadiq Public School Bahawalpur.

Solved MCQs

  1. Ratio of angular speed (minute:hour hand): 12:1

Solved Short Questions

  1. Prove v = rω → s = rθ → v = ds/dt = r dθ/dt = rω
  2. Prove a = rα → v = rω → a = dv/dt = r dω/dt = rα

Solved Numerical Problems

  1. Laser divergence: d=2.5 m, D=3.8×10⁸ m → θ = 2.5 / 3.8×10⁸ = 6.6×10⁻⁹ rad
  2. Car wheel: v=108 km/h=30 m/s, r=0.3 m → ω=100 rad/s, f≈16 rev/s
  3. Motor stop: ω₀=1800 rpm=30 rev/s, t=20 s → θ=300 rev
  4. Vertical circle max speed: r=0.5 m, T_max=35.6 N, m=0.5 kg → v≈5.5 m/s
  5. Flywheel torque: ω₀=2100 rpm=70π rad/s, t=180 s, I=38 kg·m² → τ≈44 N·m
  6. Sphere I: M=200 kg, R=0.3 m → I=(2/5)MR²=7.2 kg·m²
  7. Satellite speed: r=6.6×10⁶ m → v≈7.77 km/s
  8. Artificial gravity: r=20 m, ω=0.5 rad/s → a=5 m/s²
  9. I from L: L=10 kg·m²/s, ω=2 rad/s → I=5 kg·m²
  10. Diver: I₁=18, I₂=3.6 kg·m², ω₂=4π rad/s, t=1.5 s → θ=0.6 rev

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